Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100
L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
0.45H = 42 - 15 = 27
H = 27/.45 = 60 lbs
Back substitution, L = 40 lbs.
Answer:
To convert this fraction to a decimal, just divide the numerator (5) by the denominator (8): 5 ÷ 8 = 0.625. So,
5/8 = 0.625
Rounded values:
5/8 = 1 rounded to the nearest integer5/8 = 0.6 rounded to 1 decimal place5/8 = 0.63 rounded to 2 decimal places
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Step-by-step explanation:
This describes the commutative property of multiplication which says that
![a\times b=b\times a](https://tex.z-dn.net/?f=a%5Ctimes%20b%3Db%5Ctimes%20a)
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20 will be the answer when x=4
Answer:
zeleh
Step-by-step explanation:
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