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zysi [14]
4 years ago
14

The typical exponential function, y = ax, has asymptote ________ and y-intercept ________.

Mathematics
2 answers:
ludmilkaskok [199]4 years ago
7 0

Answer: B) The typical exponential function, y = ax, has asymptote the x-axis and y-intercept x = 0.

Step-by-step explanation:

For the funcion y = a^x, the asymptote is the value that the function would never assum, but gets really close. In this case, there is no value for y = 0, becausey = a^x\\0 = a^x \\ln(0) = x.lna\\ln(0)is not defined! This way, asymptote is x-axis (y=0).

y-intercept ⇒ x=0, so

y=a^x\\y=a^0=1

This, way, the point (0,1)

alternative b

Marina86 [1]4 years ago
5 0
The typical exponential function, y = ax, has asymptote y = 0 and <span>y-intercept (0,1). The correct option among all the options that are given in the question is the second option or option "B". The other choices are incorrect and can be easily negated. I hope that this is the answer that has actually come to your help.</span>
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Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x
Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: y=mx+b where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation  y=mx+b where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

y=mx+b\\y=-\frac{2}{3}x+3

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

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3 years ago
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45.5%  (another way to write 45  1/2 %
= .455  or 455/1000

Reducing by 5 we get 91/100

How did I get 91/100? I divided 455/1000 by  5 (numerator and denominator) And I got 91/100
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Answer:

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Step-by-step explanation:

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Answer:

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1. Subtract the linear expressions.
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