7 + 2(x - 3) + 5x
= 7 + 2x - 6 + 5x <em>distributed 2 into x - 3</em>
= 7 - 6 + 2x + 5x <em>grouped like terms together</em>
= 1 + 7x
You didn't provide an image of the steps but hopefully you can figure it out based on the information I provided.
Answer:
Step-by-step explanation:
Step-by-step explanation:
what is the problem ? what needs to be done ?
all that you are showing here is the definition of a number range.
it means all numbers, for which 1.3 is smaller or equal.
in short, all numbers that are greater or equal to 1.3.
Answer:
In inequality notation:
Domain: -1 ≤ x ≤ 3
Range: -4 ≤ x ≤ 0
In set-builder notation:
Domain: {x | -1 ≤ x ≤ 3 }
Range: {y | -4 ≤ x ≤ 0 }
In interval notation:
Domain: [-1, 3]
Range: [-4, 0]
Step-by-step explanation:
The domain is all the x-values of a relation.
The range is all the y-values of a relation.
In this example, we have an equation of a circle.
To find the domain of a relation, think about all the x-values the relation can be. In this example, the x-values of the relation start at the -1 line and end at the 3 line. The same can be said for the range, for the y-values of the relation start at the -4 line and end at the 0 line.
But what should our notation be? There are three ways to notate domain and range.
Inequality notation is the first notation you learn when dealing with problems like these. You would use an inequality to describe the values of x and y.
In inequality notation:
Domain: -1 ≤ x ≤ 3
Range: -4 ≤ x ≤ 0
Set-builder notation is VERY similar to inequality notation except for the fact that it has brackets and the variable in question.
In set-builder notation:
Domain: {x | -1 ≤ x ≤ 3 }
Range: {y | -4 ≤ x ≤ 0 }
Interval notation is another way of identifying domain and range. It is the idea of using the number lines of the inequalities of the domain and range, just in algebriac form. Note that [ and ] represent ≤ and ≥, while ( and ) represent < and >.
In interval notation:
Domain: [-1, 3]
Range: [-4, 0]
So first you would need to multiply each numbers....
4 x 1016 = 4064
5 x 108 = 540
Then all you would have to do is subtract 4064 from 540.
Your answer is 3524.
<span>4 x 1016 (4064) is 3,524 times larger than 5 x 108 (540).
PLEASE MARK AS BRAINLIEST!</span>
