Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

Take positive value x. You get

2. According to the previous theorem,

Then

Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

This means that you cannot find solutions of this equation. Then CD≠2 cm.
The point-slope form:

- given point
- given slope
The standard form:

<em>use distributive property</em>
<em>add
to both sides</em>
<em>subtract
from both sides</em>
<em>change the signs</em>

<em>Answer</em>
D) 1
<em>Explanation</em>
A perpendicular line makes a angle of 90° with a line or a plane.
If a line is to be drawn from a point to a line or a plain it can only be one. In this case a line is to be drawn through a point A to a plane P. If the line is to be perpendicular, then is is only one.
From the choices, the appropriate answer is D) 1
To do this, you'll have to get loris and doris to the same amount of time, we can already tell loris makes 40 bracelets in 100 minutes but we are still missing 20 minutes, so we got to do some math(Ofc we do its mathematics) if you divide 50 by 20 you'll get 2.5 which is how many minutes it takes to make a bracelet. So now we can go back to that missing 20 minutes, if you divide 20 by 2.5, you'll get 8. So in 2 hours loris makes 48 bracelets(20 + 20(50 hours each)=40 + 8(the missing 20 minutes) = 48) But here is the tricky part it says per an hour, so we need to reduce both by half, so loris makes 24 bracelets an hour and doris makes 22 bracelets an hour so loris makes 2 more bracelets and hour than doris... hope i've helped!
Perimeter of square = 4s perimiter of pentagon= 5s, i guess? its a regular one afterall 4s = P 4 (10) = p 40 = P (40 = 5s)/ 5 8 = s
Sorry I dont know how to answer the second one...