Differnce of 2 pefect squares
a^2-b^2=(a-b)(a+b)
(p^2)^2-9^2=(p^2-9)(p^2+9)
p^2-9=(p-3)(p+3)
factored is
(p-3)(p+3)(p^2+9)
Answer: 2/8 < 3/5 < 3/4 < 5/6
Answer:
The answer is B. 
Step-by-step explanation:
...
Vol (pyr) = 1/3 b × h, where h = 15 and b = base = area of triangular base = 1/2 b×h, where h = 12 and b = 13
V = 1/3 (1/2×12×13)×15
V = (1/3×1/2×12)×13×15
V = 2×13×15 = 30×13 = 390 in^3