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3 years ago

Easy question please help

Mathematics

1 answer:

GuDViN [60]3 years ago

7 0

An equation to represent this would be 12x+2=T.

x=10 people per large table.

If T=122 then we just have to isolate x on one side of the equation. The first step is to replace T with 120 and then subtract 2 on both sides (to cancel the +2) to get 12x=120. Cancel the 12 by dividing both sides by 12 to get x=10. The number of people seated at each large table would be 10. Hopefully I explained this correctly and helped you understand.

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Mrs. Wilson packed supply bags for her students to use in a science experiment. In each bag she put 3 rubber bands and 4 paper c

n200080 [17]

Answer:

Step-by-step explanation:

In each supply bag, Mrs. Wilson packed 3 rubber bands and 4 paper clips for her students.

Now, it is given that she had used 48 rubber bands.

Hence, there will be (48/3) =16 supply bags that had been used.

Now, in 16 supply bags, there will be (16×4) =64 paper clips.

Therefore, 64 paper clips that she had used. (Answer)

3 0

3 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes