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3 years ago

If my diameter is 35.64 what is my circumference

Mathematics

2 answers:

alexgriva [62]3 years ago

5 0

Answer:

55.9548

Step-by-step explanation:

35.64 ÷ 2 = 17.82

17.82 × 3.14 = 55.9548

Marina CMI [18]3 years ago

5 0

Answer: 111.97

Step-by-step explanation:

Circumference of a circle= 2πr

r= d/2

diameter= 35.64

Therefore circumference= 2*(3.14)*(35.64/2)

= 111.97

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Si colocan en 16 pisos, 16 ladrillos. ¿Cuántos ladrillos pusieron en total?. (expresarlo en forma de potencia)

inn [45]

Answer:

Númer total de ladrillos= 256

Step-by-step explanation:

Dada la siguiente información:

Total de pisos= 16

Total de ladrillos por piso= 16

Para calcular cantidad de ladrillos en total, tenemos que usar la siguiente formula:

Número total de ladrillos= total de ladrillos^2

Número total de ladrillos= 16^2

Númer total de ladrillos= 256

En este caso lo hace al cuadrado por que la cantidad de pisos y ladrillos por piso es la misma. Sino, es mejor expresarlo como una multiplicación.

5 0

3 years ago

If the permutions of the letters in the word SURE are numbered 1 through 24 in alphabetical order, what number is RUSE?

katovenus [111]

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7 0

3 years ago

Read 2 more answers

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$