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Mars2501 [29]
3 years ago
12

What is the area of a right triangle 21 centimeters wide and 13 centimeters tall?

Mathematics
2 answers:
Alona [7]3 years ago
6 0
Sydalexandrea_15 add me on snap
TiliK225 [7]3 years ago
4 0

Answer:

136.5 square centimetres

Step-by-step explanation:

Area of a right triangle = 1/2 tall x wide

The area = 1/2 x 21 cm x 13 cm = 136.5 cm^2

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Find the greatest common factor of the following monomials: 20a 46a^2 48a^6​
Ierofanga [76]
60a^5 is the answer to your question
6 0
2 years ago
Can someone please tell me the answer on this.
marishachu [46]

Answer: x = 31

Step-By-Step:

<u>To Find x:</u>

<u />\left(2x+20\right)+\left(x+10\right)+\left(2x-5\right)=180 (Angle Sum Property Of Triangles)

(Remove the brackets)

<u />2x+20+x+10+2x-5=18<u />

(Group Accordingly)

<u />2x+x+2x+20+10-5=180<u />

= 5x+20+10-5=180

= 5x\:+\:25 =180

= 5x= 180 - 25

= 5x = 155

= x=\frac{155}{5}

= 31

<u>Therefore</u> x = 31

So,

Angle A = x + 10 = 31 + 10 = 41

Angle B = 2*x + 20 = 2*31 + 20 = 82

Angle C = 2*x - 5 = 62 - 5 = 57

5 0
2 years ago
If 3 quarts of paint are needed for 50 ft of fence, how many quarts are needed for 300 ft of fence?
Zina [86]

Answer:

18

Step-by-step explanation:

First, you would do a proportion

\frac{3}{50}=\frac{x}{300}

Then you would cross multiply, getting 50x=900.

After that, you would do 900/50, which is 18.

5 0
2 years ago
For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr
pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

X_i Bin (1,p) = Be(p) bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

E(Z) = Mpq

Var (Z) = Mpq(1-pq)

The deduction is based on the definition of independent random variables, we can do this:

E(Z) = E(N) E(X) = Mq (p)= Mpq

And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]

And as we can see then we can conclude that   Z \sim Bin (M, pq)

8 0
3 years ago
Which of the following are true statements about any regular polygon? Check all that apply. A. all of it's angles measure 90 deg
dmitriy555 [2]

Answer:

B,E,F

Step-by-step explanation:

7 0
3 years ago
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