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andrezito [222]
3 years ago
10

Find the value of x in the following triangle

Mathematics
1 answer:
seropon [69]3 years ago
5 0
61 + 86 = 147

180 - 147 = 33

x = 33

the interior sum of angles is equal to 180 , in order to find x you would use the already established values of two corners and find the missing value
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Solve:
harina [27]

Answer:

x = 0

Step-by-step explanation:

Write the number in exponential form with the base of 2:

{2}^{x - 3}  =  {2}^{ - 3}

Since the bases are the same, set the exponents equals.

x - 3 =  - 3

Cancel equal terms on both sides of the equation:

x = 0

8 0
3 years ago
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ASAP!!!!!!!<br><br> y-13=4(x-2)
Juliette [100K]
Y-13=4(x-2)
y-13=4x-8
y=4x+5
5 0
3 years ago
Two sides of a triangle have lengths of 18 and 29 units. if the third side has an integer length, what is the positive differenc
Andru [333]
Triangular inequality:  Length of third side must be less than the sum of the lengths of the other 2 sides.
x < 18 + 29
x < 47

so Maximum length of third side is 46 units.

Also 29 < 18 + x
x > 11    so minimum length = 12

Difference  = 46-11 = 35
3 0
3 years ago
A 1300 kg car moving at 5.2 m/s is initially traveling north in the positive y direction. After completing a 90° right-hand turn
stich3 [128]

Answer:

a. 6760(i - j) kgm/s b. -6760i kgm/s c. 2172.74 N d. 19314.29 N e. 45°

Step-by-step explanation:

Given that mass of car, m = 1300 kg

initial velocity in the y-direction, v₁ = 5.2j m/s

time taken for 90° turn to positive x-direction, t₁ = 4.4 s

time taken for collision in positive x-direction, t₂ = 350 ms

a. Impulse, J₁  on car during turn.

impulse, J =mv₂ - mv₁

v₁= initial velocity and v₂ = final velocity

v₁ = 0i + 5.2j m/s since it was initially moving in the positive y-direction.

v₂ = 5.2i + 0j m/s since it was initially moving in the positive x-direction.

So, J₁ = m(5.2i + 0j -(0i + 5.2j))

          = m(5.2i - 5.2j)

         = 1300× 5.2(i-j)

         = 6760(i-j) kgm/s

b. Impulse after collision J₂

v₁= initial velocity=5.2i + 0j m/s since it was initially moving in the positive x-direction.

v₂= 0m/s since the car stops after collision

So, J₂= mv₂ - mv₁

         = m(0 - (5.2i + 0j)) m/s

         =-5.2mi kgm/s

         = -1300 × 5.2i kgm/s

         =-6760i kgm/s

c. Average force, F₁ during turn

Impulse J = Ft

From (a) the impulse J₁ = 6760(i-j) kgm/s. The time taken for the turn t₁ = 4.4 s. So, F₁ = J₁/t₁ = 6760(i-j)/4.4 = 1536.36(i-j) N.

Magnitude of F₁ = F₁ = average force during turn=1536.36√2= 2172.74 N

d. Average force, F₂ after collision

From J=Ft, F=J/t

From (b) above, our impulse during collision is J₂ = -6760i kgm/s. The time taken for the impulse or collision to occur is t₂ = 350 ms.

So, F₂ = J₂/t₂ = -6760i /(350 × 10⁻³) N= - 19314.29i N.

So magnitude of F₂= F₂=average force during collision = 19314.29 N

e. Angle between average force in (c) and the positive x- direction.

We know that F₁= 1536.36(i-j) N = 1536.36i - 1536.36j N. The unit vector in the positive x-direction is i.

For the angle between two vectors, we have that cosθ= a.b/ab where a,b are vectors and a,b their magnitudes respectively.

So, cosθ = (1536.36i - 1536.36j).i/(1536.36√2) =1536.36/1536.36√2=1/√2

cosθ = 1/√2

θ=cos⁻¹(1/√2)

θ=45°

4 0
3 years ago
The width of a rectangle is 3 units less than the length. The area of the rectangle is 54 units. What is the length,in units of
My name is Ann [436]

Answer:

The length is 9 units

Step-by-step explanation:

Let x = length

width  = x-3

Area = 54 = l*w

54 = x * (x-3)

Distribute

54 = x^2 -3x

Subtract 54 from each side

54-54 = x^2 -3x-54

0 =  x^2 -3x-54

Factor

What 2 number multiply to -54 and add to -3

-9 * 6 =54

-9+6 =-3

(x-9) (x+6) =0

Using the zero product property

x=9   x=-6

Since we cannot have negative length

x=9 units

The length is 9 units

5 0
3 years ago
Read 2 more answers
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