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3 years ago

1 3/7 x 2 3/4 fraction plz

Mathematics

1 answer:

maksim [4K]3 years ago

7 0

Answer:

$\frac{55}{14}$

Step-by-step explanation:

First, we convert the mixed numbers into improper fractions: $1\frac{3}{7} =\frac{10}{7}$ , and $2\frac{3}{4}=\frac{11}{4}$ . Now, we multiply the fraction using the multiplication rule, $\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}$ : $\frac{10}{7} \times \frac{11}{4} = \frac{110}{28} = \frac{55}{14}$ .

Thus, the product of the two given fractions is 55/14.

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45 + 60= 105
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45/ 105
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4 years ago

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The Wheel Shop sells other kinds of vehicles. There are bicycles and go-carts in a different room of the shop. Each bicycle has

Alisiya [41]

Answer:

15 bikes, 6 gocarts

Step-by-step explanation:

so both the vehicles have 1 seat each

the bicycles will be represented by B

the gocarts will be represented by G

because there are only 1 seat per for a total of 21 seats, we have this as the first equation:

B + G = 21

Gocarts have wheels and bikes have 2 seats, so we have this equation:

2B + 4G = 54

from there we can simply replace b with g to find the amount of gocarts first:

B + G = 21

B = 21 - G

2(21-G) + 4G = 54

42 - 2G + 4G = 54

2G + 42 = 54

2G = 12

G = 6

So there are 6 gocarts.

plug in 6 for g

B + 6 = 21

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therefore, there are 15 bikes and 6 gocarts

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3 years ago

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Which graph shows the solution set.

Ede4ka [16]

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I NEED HELP ASAP

SIZIF [17.4K]

Answer:

It is not reasonable that the state education department claims the percentage for the entire state is 73%.

Step-by-step explanation:

We are given that 191 of the 288 high school students surveyed at a local school said they went outside more during school hours as elementary school students than they do now as high school students.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of high school students who went outside more during school hours as elementary school students than they do now as high school students = $\frac{191}{288}$ = 0.66

n = sample of high school students = 288

p = population percentage for the entire state

Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.

The margin of error is given by;

M.E. = $2 \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

= $2 \times \sqrt{\frac{0.66(1-0.66)}{288} }$

M.E. = 0.056 or 5.6%

So, the confidence interval so formed = $\hat p \pm \text{Margin of error}$

= [ $0.66 - 0.056 , 0.66 + 0.056$ ]

= [0.604, 0.716]

Since the above interval does not include 0.73 or the population proportion of 73% falls outside the above interval. So, it is not reasonable that the state education department claims the percentage for the entire state is 73%.

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3 years ago