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OLga [1]
3 years ago
12

Rachel withdraws ​$18 from the bank account once each day for six days. What integer represents the change in the amount in the​

account? Use a pencil and paper. Find the integer that would represent the change in the amount in the account if Rachel deposits ​$18 into her bank account once each day for six days. Explain the difference between the integer for the withdrawals and the integer for the deposits.
Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

-108

108

Step-by-step explanation:

Since it is withdrawing, we are taking away -$18 every day for 6 days.

(-18)*6 = -108

Since it is deposits, we are adding to the amount in her account, +$18 for 6 days.

18*6 = 108

The difference is that one is taking away and one is adding each day, resulting in negative or positive change.

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Answer:

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Minimum is a 4th Degree

2)

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x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

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Step-by-step explanation:

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