<em>The question has inconsistent or incomplete data, so I'm filling the holes with key data.</em>
Answer:
<em>Every people at dinner received one-tenth of the original turkey= 0.1</em>
Step-by-step explanation:
<u>Proportions</u>
If some fraction a/b of a whole total M is to be computed and later removed, we proceed as follows
* Compute the portion to be removed as a/b*M
* Subtract it from the total quantity: M-a/b*M=M(1-a/b)
I'm assuming 1/5 of the turkey was lost due to overcooking. It means that (1-1/5) of the turkey remained for dinner, that is, 4/5 of the turkey.
Each people at dinner received the same amount of the remaining, so we must divide 4/5 by 8, to get 4/40, or 1/10. It means that every people at dinner received one-tenth of the original turkey
I guess you need to find what E is, though sadly this isnt enough information to me....
You would:
(4 * 2 - 4) + (3 - 2^2) + (2 * 2^3)
(8 - 4) + (3 - 4) + (16)
4 + -1 + 16 = 19
9514 1404 393
Answer:
- common denominator: (x² -4)
- simplified complex fraction: (2x +1)/(9 -2x)
Step-by-step explanation:
It is helpful to remember the factoring of the difference of squares:
a² -b² = (a -b)(a +b)
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Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.
It looks like you want to simplify ...
![\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cleft%28%5Cdfrac%7B2%7D%7Bx-2%7D-%5Cdfrac%7B3%7D%7Bx%5E2-4%7D%5Cright%29%7D%7B%5Cleft%28%5Cdfrac%7B5%7D%7Bx%5E2-4%7D-%5Cdfrac%7B2%7D%7Bx%2B2%7D%5Cright%29%7D%3D%5Cdfrac%7B%5Cleft%28%5Cdfrac%7B2%28x%2B2%29%7D%7B%28x-2%29%28x%2B2%29%7D-%5Cdfrac%7B3%7D%7B%28x-2%29%28x%2B2%29%7D%5Cright%29%7D%7B%5Cleft%28%5Cdfrac%7B5%7D%7B%28x-2%29%28x%2B2%29%7D-%5Cdfrac%7B2%28x-2%29%7D%7B%28x-2%29%28x%2B2%29%7D%5Cright%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2%28x%2B2%29-3%7D%7B5-2%28x-2%29%7D%3D%5Cboxed%7B%5Cdfrac%7B2x%2B1%7D%7B9-2x%7D%7D)
X=6 and x=1
You can find your zeros by determining what you have to plug into the function in order for it to equal zero
If we plug in 6, for example we’d get (6-6)(x-1)
Simplified this is 0(x-1)
Anything times 0 is 0, so this is one of our zeros.
Same goes for x-1, we just need to plug in 1 for it to equal 0
Therefore there are zeros at x=1 and x=6 :))