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ss7ja [257]
3 years ago
5

Find the area of a regular octagon with an apothem of 7 inches and a side length of 5.8 inches. (nearest tenth)

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

162.4 in²

Step-by-step explanation:

LETS GET INTOOOOEEETTT

Let's start with what we know:

Area of regular octagon = 1/2 x perimeter x apothem

We know the apothem, so all that we need to find to fill in the above equation is the perimeter:

perimeter = 8 x 5.8 = 46.4in

Now we can fill in our original equation and solve:

Area of regular octagon = 1/2 x perimeter x apothem

Formula = n (s/2)² divided by tan( π /n)

   = 8 (5.8/2)²  divided by tan ( π /8)

                 = 162.4283 in²

ORRR when rounded to the nearest tenth,

                      =162.4 in²

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The top portion of this graph would be y = 4

The bottom portion would be y = x - 1


In order to find both of these, we have to look at them separately. Let's start with the flat line between 1 and -1. Since it is between those numbers, we know this one goes on top. We also know that since the line is horizontal, that the equation must be y = the number that it sits at. This is the definition of a horizontal line. Since the line is at 4, we get y = 4.


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m = (y1 - y2)/(x1 - x2)

m = (4 - 2)(5 - 3)

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3 years ago
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Step-by-step explanation:

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