A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:
(x,y)→(y,-x).
Then:
- D(−2,4)→D'(4,2)
- E(4,7)→E'(7,-4)
- F(10,3)→F'(3,-10)
- G(8,0)→G'(0,-8)
Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).
Y= 8x-9, because I need more characters
Correlation because it is not saying that evenings cause him to run slower
<u><em /></u><em />The correct answer to the question above is 4/13. Below it shows how it's achieved...<u><em>
EQUATION:</em></u>
P(A|B) = <u>P(A ∩ B)
</u> P(B)
<u>
</u>Step 1: Identify
P(B) = 5/14
P(A ∩ B) = 10/91
<u>
</u>Step 2: Insert into the equation and Solve
10/91 ÷ 5/14
Use reciprocal to divide
10/91 × 14/5
Simplify the answer
140/455
Simplified (Final Answer)
4/13
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</u>
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</u>
Answer:
![\frac{x^3-a^3}{0}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3-a%5E3%7D%7B0%7D)
Step-by-step explanation:
![\frac{x^4-a^4}{x-a}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E4-a%5E4%7D%7Bx-a%7D)
divide by x-a
![\frac{x^3-a^3}{0}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3-a%5E3%7D%7B0%7D)