The given line has a slope of -1 so the perpendicular line will have a slope of -1/1=1
y=x+5
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
X values are increasing by 2
y values are increasing by 4
Mark is correct
Answer:
B = 15
Step-by-step explanation:
<u>Combine multiplied terms into a single fraction</u>
6 + 2b/5 = 12
<u>Subtract 6 from both sides</u>
6 + 2b/5 <em>(-6)</em> = 12 <em>(-6) </em>= 2b/5 = 6
<u>Multiply all terms by the same value to eliminate fraction denominators</u>
2b/5 <em>( x 5) </em>= 6<em> (x 5)</em>
<em />
<u>Simplify</u>
2b = 30
Answer: option c
Step-by-step explanation:
Find the x-intercept and y-intercept of each line.
To find the x-intercept, substitute 
into the equation and solve for "x".
To find the y-intercept, substitute 
into the equation and solve for "y".
- For the first equation:
x-intercept
y-intercept
Graph a line that passes through the points (7.25, 0) and (0, 9.66)
- For the second equation:
x-intercept
y-intercept
Graph a line that passes through the points (0.5, 0) and (0, -0.33)
Observe the graph attached. You can see that point of intersection of the lines is (5,3); then this is the solution of the system. Therefore:
