POH = -log [OH-]
pOH = - log (1 x 10^-11)
pOH = -(-11) = 11
pH + pOH = 14
pH + 11 = 14
pH = 14 - 11 = 3
Answer:
4 biological membranes.
Explanation:
So in total, your water molecule has to go through your cell membrane, reach the outer membrane of your chloroplast and then through the inner membrane, and then lastly, it has to go through your thylakoid membrane to reach its final destination of the illumine. So in total 4 biological membranes.
Answer:
0.002389
Explanation:
look at the first non-zero digit if rounding to one significant figure
look at the digit after the first non-zero digit if rounding to two significant figures
draw a vertical line after the place value digit that is required
look at the next digit
if it's 5 or more, increase the previous digit by one
if it's 4 or less, keep the previous digit the same
fill any spaces to the right of the line with zeros, stopping at the decimal point if there is one
Answer:
2.11 g hydrobromic acid (correct to 3SF)
Explanation:
Molecular formula of hydrobromic acid = C2H5BrO2
mass of C2H5BrO2 = 140.96g
Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.
It looks like this:
9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2
