15.6gC3H8*44.1gC3H8*32gO2=11.32
B protons are positive atoms and are inside the nucleus
Answer:
The activation energy for this reaction = 23 kJ/mol.
Explanation:
Using the expression,

Where,


is the activation energy
R is Gas constant having value = 8.314×10⁻³ kJ / K mol

The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (280 + 273.15) K = 553.15 K
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (376 + 273.15) K = 649.15 K
So,




<u>The activation energy for this reaction = 23 kJ/mol.</u>
The formula for Lithium Iodide is LIL
Answer:
6.4924249 × 10^-23 g you need to solve it