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3 years ago

¿Cómo se llama el grupo IIA de la tabla periódica?

Chemistry

1 answer:

Verdich [7]3 years ago

8 0

Answer:

los metales alcalinotérreos: berilio (Be), magnesio (Mg), calcio (Ca), estroncio (Sr), bario (Ba) y radio (Ra).

o simplemente llamado grupo 2A

Explanation:

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2. Calculate the pressure in Pa of a brick, which weighs 40 lbs (178N) sitting flat on the

Aloiza [94]

Answer:

P = 741.7 Pa

Explanation:

Pressure:

It is the force applied on object per unit area. The force is applied perpendicular to the surface.

Mathematical expression:

P = F/A

P = pressure

F = force

A = area

Given data:

Weight = 178 N

Area = 10 cm × 24 cm

Pressure = ?

Solution:

Area = 10 cm × 24 cm

Area = 240 cm²

Area = 240 /10000 = 0.024 m²

Formula:

P = F/A

P = 178 N / 0.024 m²

P = 741.7 Nm⁻²

Nm⁻² = Pa

P = 741.7 Pa

6 0

3 years ago

Sarah added sugar to her iced tea but it is not dissolveing very quickly which can Sarah do to make the sugar dissolve faster ?

Aliun [14]

Stir it,
Or as warmer water makes solutes dissolve faster Sarah can do that

7 0

3 years ago

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

What would the Net Ionic Equation be for the following:

marin [14]

The net equations are obtained from the double displacement of the cations and anions, then balance.

NH3(aq) + HC2H3O2 (aq) = NH4+(aq) + C2H3O2-(aq)
H+(aq) + C2H3O2-(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq)

2NaOH(aq) + H2SO4 (aq) = Na2SO4 (s)+ 2H2O (aq)
H2S (aq) + Ba(OH)2 (aq) = BaS (s)+ 2H2O (aq)

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3 years ago

What is the mass of 22.4 L of H2 at STP? (5 points)

cestrela7 [59]

11.2
Step-by-step-explanation

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3 years ago

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