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2 years ago

Answer

Mathematics

2 answers:

sergij07 [2.7K]2 years ago

3 0

Answer:

Answer:

1). Option (A)

2). Option (A)

Step-by-step explanation:

1). A worker bee has the mass = 0.00011 kg

In scientific notation we can convert the mass of bee as,

0.00011 =

Since 1.1 ≈ 1,

Therefore, 1.1 × 10⁻⁴ ≈ 1 × 10⁻⁴ kg

Option (A) is the answer.

2). An African elephant has a mass = 8139 kg

In scientific notation,

8139 = 8.139 × 10³

Since, 8.139 ≈ 8

Therefore, 8139 kg = 8.139 × 10³ kg

Option (A) is the answer.

Step-by-step explanation:

Hope this helps! ;)

Pepsi [2]2 years ago

3 0

Answer:

The investment of $10,000 decreases by 2% every year. So the following year is usually (100 - 2)=98% of the previous year. This is a geometric progression.

In this case the first term = 10000

The second term = 98% × 10000 = 9800.

The common ratio = 9800/10000=49/50

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98.

The equation of the exponential rate would be;

10,000ₓ0.98ⁿ.

where n is the number years.

Step-by-step explanation:

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2 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

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