Please help! Probability!!
1 answer:
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Answer:
No Options
∠QOB=45º
Step-by-step explanation:
we have that: point O=Incenter, sides S, Q, R they form right angles with the point O, angle OBC = 15º and angle OCR=30º, find angle QOB
we know that the sum of all the internal angles of a triangle is 180º, so
α =180-30-15-90=45º and β = 180-90-α → β = 180-90-45 =45º,
Finally β=∠QOB=45º
<h2>a. What is your equation?</h2>
This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:
Where:
So:
Finally, the equation is:
The rocket will reach the maximum height at the vertex of the parabola described by the equation . Therefore, our goal is to find
at this point. In math, a parabola is described by the quadratic function:
So the x-coordinate of the vertex can be calculated as:
From our equation:
So:
So the rocket will take its maximum value after 1.99 seconds.
<h2>c. What is the maximum height the rocket will reach?</h2>
From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by . Thus, we can find this as follows:
So the maximum height the rocket will reach is 66.68ft
<h2>d. How long is the rocket in the air?</h2>
The rocket is in the air until it hits the ground. This can be found setting , so:
We can't have negative value of time, so the only correct option is and rounding to the nearest hundredth we have definitively: