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3 years ago

In this figure, A'B'C'D'is a transformation of ABCD.

Mathematics

1 answer:

siniylev [52]3 years ago

6 0

Answer:

translation and um thats all

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Convert the function into standard form. Show your work. y-2=-3(x+4)^2

Sonja [21]

Answer:

y = -3x² - 24 x + 50

Step-by-step explanation:

y - 2 = - 3(x+4)²

y - 2 = -3(x²+8x+16)

y - 2 = -3x² -24x +48

y = -3x² - 24 x + 50

8 0

3 years ago

Read 2 more answers

A jet plane carry up to 200,000 liters of fuel. It used 130,000 of fuel during the flight what is the %

S_A_V [24]

Answer:

65%

Step-by-step explanation:

Given that,

Total fuel = 200000 L

Used fuel = 130,000 L

We need to find the percentage of the used fuel. It can be given by :

$\%=\dfrac{130,000}{200000}\times 100\\\\=65\%$

So, the required percentage is 65%.

8 0

3 years ago

The width of a rectangle is 4 inches (in) and the area of the rectangle is 32 in2? Which of the following represents the length

miv72 [106K]

Answer:

A. 8

Step-by-step explanation:

32 divided by 4 = 8

5 0

3 years ago

The height of a trapezoid is 26 yards and the bases are 14 and 30 yards. What is the area (in square yards)?

faust18 [17]

Answer: 572 yards

Step-by-step explanation:

The equation to find the area of a (base1 + base2) x height/2

The two bases are 14 and 30. Add them up to get 44.

Then, times that by the height. You get 1,144.

Lastly, divide 1,144 by 2. You get 572.

I hope this helped!

5 0

2 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

For the question a * you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

For question b, do the same procedure.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

Finally for the question c we have

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

8 0

3 years ago