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2 years ago

ANSWER QUICK! BRAINLIEST IF RIGHT!

Mathematics

2 answers:

erik [133]2 years ago

8 0

Let another angle be x

According to angle sum property

$\\ \rm\Rrightarrow x+35+78=180$

$\\ \rm\Rrightarrow x+113=180$

$\\ \rm\Rrightarrow x=180-113$

$\\ \rm\Rrightarrow x=67°$

Solnce55 [7]2 years ago

4 0

67°, every triangle equals 180° so add together 35+78 which equals 113. subtract 180-113 and get 67!

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1. You order books through a catalog. Each book costs $12 and the

kotykmax [81]

Answer:

y=12x+5

Step-by-step explanation:

y = the total cost

x = the number of books ordered

12x because each book (x) is $12

+5 because shipping and handling is an initial charge of $5

a. y=12(6)+5

y=72+5

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b. y=12(4)+5

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4 years ago

HELP BRAINLY PPLS!!! Identify the transformation that was applied to this boomerang.

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3 years ago

According to survey data, the distribution of arm spans for males is approximately Normal with a mean of 71.4 inches and a stan

Gekata [30.6K]

Answer:

a) 89.97% of men have arm spans between 66 and 76 inches.

b) The z-score for this person's arm span is 5.68. 0% of males have an arm span at least as long as this person

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71.4 inches and a standard deviation of 3.1 inches.

This means that $\mu = 71.4, \sigma = 3.1$

a. What percentage of men have arm spans between 66 and 76 inches?

The proportion is the pvalue of Z when X = 76 subtracted by the pvalue of Z when X = 66. The percentage is the proportion multiplied by 100.

X = 76

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{76 - 71.4}{3.1}$

$Z = 1.48$

$Z = 1.48$ has a pvalue of 0.9306

X = 66

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{66 - 71.4}{3.1}$

$Z = -1.74$

$Z = -1.74$ has a pvalue of 0.0409

0.9306 - 0.0409 = 0.8997

0.8997*100% = 89.97%

89.97% of men have arm spans between 66 and 76 inches.

b. A particular professional basketball player has an arm span of almost 89 inches. Find the z-score for this person's arm span. What percentage of males have an arm span at least as long as this person?

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{89 - 71.4}{3.1}$

$Z = 5.68$

The z-score for this person's arm span is 5.68.

Z = 5.68 has a pvalue of 1

1 - 1 = 0

0% of males have an arm span at least as long as this person

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3 years ago

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25 days

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Answer:

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3 years ago

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