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Sergio [31]
3 years ago
15

GUYSSSSS!!!! PLEASE I NEED HELP RIGHT NOWW!!! HELP PLEASE!​

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

\angle ABC=20^{\circ}

Step-by-step explanation:

Since each side of a line is 180 degrees, we can write the following system of equations:

\begin{cases}2x+12y+x+2y=180,\\x+2y+8y-4x=180\end{cases},\\\begin{cases}3x+14y=180,\\-3x+10y=180\end{cases}

Add both equations to solve for y:

24y=360,\\y=\frac{360}{24}=15

Now substitute y=15 into 3x+14y=180 to solve for x:

3x+14(15)=180,\\3x=-30,\\x=-10

Finish by substituting both variables to solve for \angle ABC:

\angle ABC=x+2y,\\\angle ABC=-10+2(15),\\\angle ABC=-10+30=\boxed{20^{\circ}}

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<h3>Answer: D.  (2, 21)</h3>

Explanation:

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(-3+7)/2 = 4/2 = 2

The value 2 is right in the middle of -3 and 7 on the number line. This result is also the x coordinate of the midpoint since the values I used were the x coordinates of the original points.

The y coordinates are handled the same way:

(18+24)/2 = 42/2 = 21

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Overall, the midpoint is (2, 21)

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Answers:

<u>Reduce:</u>

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Grouping similar terms:

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Applying common factor x^{2} in the first parenthesis and common factor 2 in the second parenthesis:

x^{2}(1+\frac{12}{x^{4}})+2(9x+14) This is the answer

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Rearranging the terms:

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Applying common factor y in the first parenthesis and common factor 3 in the second parenthesis:

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19) (\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})

Multiplying both fractions:

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\frac{12 c^{3}}{105 c a^{4}u} This is the answer

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Operating with cross product:

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Grouping similar terms and factoring:

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Simplifying:

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Factoring numerator and denominator:

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Simplifying:

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Applying the distributive property in numerator and denominator:

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Answer:

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Step-by-step explanation:

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