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3 years ago

Solve for x? pls help

Mathematics

1 answer:

Ivahew [28]3 years ago

5 0

Answer:

x = 11

Step-by-step explanation:

36/54 = (x + 5)/24

54(x + 5) = (36)(24)

54x + 270 = 864

54x = 594

x = 11

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oksian1 [2.3K]

Given :-

a² - 2a - b² = 0
2b + 2ab = 0

To find :-

Value of a and b .

Solution :-

Taking second equation:-

2b + 2ab = 0
2b ( 1 + a ) = 0
2b = 0 or (1+a) = 0
b = 0 , a = -1

Substitute in first equation :-

a² - 2a - b² = 0

When b = 0 ,

a² - 2a - 0² = 0
a² - a = 0
a( a -1) =0
a = 0 , 1

When a = -1 ,

(-1)² - 2*(-1) - b² = 0
1 + 2 - b² = 0
b² = 3
b = ±√3

Answer :-

a = 0,1 ; b = 0
a = -1 , b = ±√3

8 0

2 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

2 years ago

You have $5,000 to invest for ten years. The Bank pays simple interest at an annual rate of 5%. Calculate your balance after 10

Mazyrski [523]

Answer: $7,500

Step-by-step explanation:

Use the formula: SI = P(1 + rt)

SI = 5000(1 + 0.05[10])

SI = 5000 + 2500

SI = $7,500

After 10 years, your balance should be $7,500

3 0

2 years ago

-24 points lost on a test how many were incorrect

Luba_88 [7]

if there were 100 questions then 76 were correct, and 24 incorrect, you can simplify and rearrange the fraction depending on how many questions there were,

5 0

3 years ago

Find the compound Interest for Rs.18,800 ,calculated for 2 years at 13% rate of Interest compounded annually

Vinvika [58]

For compound interest, the formula is given below:

Amount = $P(1+\frac{r}{100} )^{n}$

Here, P = 18,800

n = 2

r = 13/100

So, Amount = $18,800(1+\frac{13}{100} )^{2}$

$18,800(1.13)^{2}$

= 18,800 × 1.2769

= 24005.72

Compound Interest = Amount - Principal

Compound Interest = 24005.72 - 18800

= 5205.72

Hence, the compound interest for Rs.18,800, calculated for 2 years at 13% rate of interest compounded annually is Rs.5205.72.

4 0

3 years ago