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V125BC [204]
3 years ago
11

If more solvent is added to a solution: a. The solution's molarity decreases. B. The solution becomes more concentrated C. The s

olution becomes supersaturated D. The solution's molarity increases
Chemistry
2 answers:
True [87]3 years ago
8 0
I think that it is b
Sergeu [11.5K]3 years ago
4 0
The correct answer is C
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Which of the following forces is responsible for accretion?
Makovka662 [10]

Answer:

It's explained by nebular theory, which describes the forces and processes at play as a nebula spins and accretes into a star and its planets orbiting it. A key piece of information to always keep in mind is that the force of gravity is responsible for accretion and all the objects it forms.

Explanation:

I hope this helps my mom helped me with this question too

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3 years ago
Help asap <br> help show work <br> I need an A
MrRissso [65]

Answer:   17 (a) 360,000 ms         18 (a) 0.245 s

                     (b) 4.800 kg                   (b) 500 cm

                     (c) 560.0 dm                  (c) 68.00 m

                     (d) 72,000 mg                (d) 0.025 Mg

<u>Explanation:</u>

Use the following table.  Note the direction you are going to:

Right means move decimal to the right. Left means move decimal to the left.

               \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

**********************************************************************************************

17(a) 360 s to ms                                                        o       →         →        →o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the right   -->   360_ _ _.

Fill in the blanks with zeroes   --> 360,000

  (b) 4800 g to kg                            o←    ←     ←         o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left   --> 4.<u>8</u> <u>0</u> <u>0</u>

<u />

 (c) 5600 dm to m                                                       o←     o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 1 place to the left   --> 560. <u>0</u>

<u />

 (d)  72 g to mg                                                         o         →        →        →o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the right   --> 72 _ _ _.

Fill in the blanks with zeroes   -->     72,000

***********************************************************************************************

18 (a) 245 ms to s                                                       o←       ←       ←        o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left -->   . <u>2</u> <u>4</u> <u>5</u>

     (b) 5 m to cm                                                        o        →        →o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 2 places to the right   -->   5 _ _.

Fill in the blanks with zeroes   -->    500

      (c) 6800 cm to m                                                 o←      ←        o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 2 places to the left   -->   68. <u>0</u> <u>0 </u>

<u />

    (d)  25 kg to Mg    o←    ←    ←    o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left -->   . _ 25

Fill in the blanks with zeroes  -->   .025

6 0
4 years ago
Ice will ________ in water.<br> A. float<br> B. sink<br> C. stay the same
Marizza181 [45]

Answer:

It floats.

Explanation:

Ice would float because it is about 9% less dense than water

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