<span>Si is reduced/Oxidizing reagent Mg is oxidized/reducing reagent</span>
Use PV =nRT. Rearrange it to n = PV/RT.
P = 202.6 kPa
V = 4.0L
R = 8.314 kPa*L/mol*K
T = 127 °C + 273 = 400 K
Plug it in and solve. I got 0.24 moles of H2.
Water , H2O, is a molecule made of oxygen and hydrogen. The bonds that hold water molecules together are due to shared ELECTRONS, and known as covalent bonds
The pH of the solution : 12
<h3>Further explanation</h3>
Reaction
HCOOH + NaOH ⇒ HCOONa + H₂O
mol HCOOH =

mol NaOH =

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]
ICE method :
HCOOH + NaOH ⇒ HCOONa + H₂O
4 5
4 4 4 4
0 1 1 1
Concentration of [OH⁻] from NaOH :

pOH=-log[OH⁻]
pOH=-log 10⁻²=2
pH+pOH=14
pH=14-2=12
Answer:
See explanation
Explanation:
The overall charge on ClO3− is shown on the image attached to this answer. If we calculate the formal charges on each atom in the structure, we will notice that one oxygen atom has a formal charge of -1 while all other atoms have a formal charge of zero.
This gives the compound an overall charge of -1 as shown in the image attached to this answer. This is the correct Lewis structure for the compound ClO3− .