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shutvik [7]
3 years ago
14

SOMEONE HELP MEEE !!!!Which description best fits the graph ?

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0
It’s decreasing then increasing. The graph starts by going down and to the right, the moves up and to the left. I hope this helps (-:
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Triangle ABC and its transformation DEF are shown. What transformation of triangle ABC produced triangle DEF?
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Answer: a

Step-by-step explanation:

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Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

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It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

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<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

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3 years ago
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yaroslaw [1]

Answer:

n= 11 & n = 13 is the answer

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Suppose that W and X are points on the number line. If WX=9 and W lies at 12, where would X be located? If there is more than on
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X = 3/4
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100 POINTS!!!!!!!!!!!!!!!!!!!!!!!!
hodyreva [135]
<h3>Key points :-</h3>

✪ Both triangles will be proven similar by AA theorem i.e. Angle-Angle theorem.

✪ The symbol for similarity is ~.

✪ The symbol for congruency is ≅.

\rule{300pt}{2pt}

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\large{|\underline{\mathtt{\red{A}\blue{n}\orange{c}\pink{i}\blue{e}\purple{n}\green{t}\red{E}\blue{n}\orange{i}\green{g}\red{m}\purple{a}\pink{29}}}}

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