0.3/10 as a decimal plz help
2 answers:
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Answer:
The 95% confidence interval for those opposed is: (0.298, 0.334).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
1786 of the 2611 were in favor, so 2611 - 1786 = 825 were opposed. Then
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for those opposed is: (0.298, 0.334).