70 POINTS!!!! PLEASE HELP I REALLY NEED HELP ESPECIALLY PART D AND F!!!!
2 answers:
Mark Brainiest please
1. 2x + 3y = 1,470
–2x –2x
3y = –2x + 1,470
3y/ 3 = –2x/3 + 1,470/3
y = –2x/3 + 490
The y-intercept of this equation is 490 and the slope is -2x/3.
2. I would graph this line by finding the y-intercept 490 first.
Then, you would move down twice from 490 to 488.
Finally, you would move to the right 3 times.
3. F(x) = –2x/3 + 490
The graph would represent the profit of Sal’s Sandwich Shop on every sandwich and wrap from the lunch specials last month.
4. View file below.
5. The graphs of these functions are similar in the fact that they are parallel to each other, therefore having the same slope.Both lines are also negative. They are different in that they do not have the same y-intercept or x-intercept.
1. 2x + 3y = 1,470
–2x –2x
3y = –2x + 1,470
3y/ 3 = –2x/3 + 1,470/3
y = –2x/3 + 490
The y-intercept of this equation is 490 and the slope is -2x/3.
2. I would graph this line by finding the y-intercept 490 first.
Then, you would move down twice from 490 to 488.
Finally, you would move to the right 3 times.
3. F(x) = –2x/3 + 490
The graph would represent the profit of Sal’s Sandwich Shop on every sandwich and wrap from the lunch specials last month.
4. View file below.
5. The graphs of these functions are similar in the fact that they are parallel to each other, therefore having the same slope.Both lines are also negative. They are different in that they do not have the same y-intercept or x-intercept.
You might be interested in
Split up the interval [2, 5] into 
equally spaced subintervals, then consider the value of 
at the right endpoint of each subinterval.
The length of the interval is
, so the length of each subinterval would be 
. This means the first rectangle's height would be taken to be 
when 
, so that the height is 
, and its base would have length 
. So the area under over the first subinterval is 
.
Continuing in this fashion, the area under over the 
th subinterval is approximated by 
, and so the Riemann approximation to the definite integral is
and its value is given exactly by taking
. So the answer is D (and the value of the integral is exactly 39).
The length of the interval is
Continuing in this fashion, the area under
and its value is given exactly by taking