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y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
Answer:
z = 61
Step-by-step explanation:
The exterior angle is congruent (equal to) the sum of the 2 farthest angles from it, so you can set the equation like this:
z + z - 11 = z + 50
Add like terms, which would be the 2 "z's" on the left side:
2z - 11 = z + 50
Then subtract the z on the right side from both sides:
2z - 11 = z + 50
-z -z
___________
z - 11 = 50
Add 11 to both sides:
z - 11 = 50
+ 11 +11
________
z = 61
Answer:
Part a) 
Part b) 
Part c) 
Part d) 
Step-by-step explanation:
see the attached figure to better understand the question
we know that
To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor
Part a) we have
The scale factor is 5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part b) we have
The scale factor is 3.7
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part c) we have
The scale factor is 1/5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part d) we have
The scale factor is s
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is
