Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
it just says PDF won't let me download I. sorry
Whatever% of anything is just (whatever/100) * anything.
thus 29.5% of something, is just (29.5/100) * something, and the decimal form of 29.5% is just 29.5/100 or the quotient of 29.5÷100.
First, 10 to the second power equals to 100. 100 divided by 3 equals to 33.33. 33.33 x 7 equals to 233.33. So the answer is 233.33.
Answer:
- 670 adult tickets
- 1340 student tickets
Step-by-step explanation:
One group of 2 student and 1 adult tickets will go for 2×$12 +16 = $40. The number of such groups sold was ...
$26,800/$40 = 670
There were 670 adult tickets sold.
There were 670×2 = 1340 student tickets sold.
