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nata0808 [166]
2 years ago
14

Anyone know the answer? :)

Mathematics
1 answer:
butalik [34]2 years ago
6 0

Answer:

angle?????

Step-by-step explanation:

???????????math

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Please , can someone answer thisss TmT
Tems11 [23]

Answer:

7

Step-by-step explanation:

We have that x1=−1, y1=5, x2=3, y2=7.

Plug the given values into the formula for a slope: m=7−(5)3−(−1)=12.

Now, the y-intercept is b=y1−mx1 (or b=y2−mx2, the result is the same).

b=5−(12)(−1)=112

Finally, the equation of the line can be written in the form y=b+mx:

y=112+x2

ANSWER

5 0
3 years ago
Read 2 more answers
Daniel paid interest of 1,020 in 5years at12%per annum on a loan. Hw much did he borrow
Marat540 [252]
I = Prt
I=1020
r=0.12 (12% converted to decimal by dividing by 100)
t=5
1020=P(0.12)(5)
1020=P(0.6)
P=1700
5 0
2 years ago
If the function f(x) = (2x - 3)2 is transformed to g(x) = (-2x - 3), which type of transformation occurred?
san4es73 [151]

Answer:

A. horizontal reflection

Step-by-step explanation:

Given:

f(x)=(2x-3)^2

g(x)=(-2x-3)^2

To identify the type of transformation.

Solution:

On close observation of the functions we find the that sign of x has changed in g(x) with other terms being constant.

<em>Thus, the transformation statement can be given as:</em>

f(x)\rightarrow f(-x)

As:

f(x)=(2x-3)^2

f(-x)=(2(-x)-3)^2= (-2x-3)^2 = g(x)

The transformation f(x)\rightarrow f(-x) describes horizontal reflection of function across the y-axis.

Thus, f(x)  is horizontally reflected across y-axis to get g(x).

8 0
3 years ago
Pleas help me please and than you! (6th grade math)
klasskru [66]

Answer:

wow u call that 6th grade

Step-by-step explanation:

I am in 8th grade and dont get this at all.

never touched the topic

6 0
3 years ago
Can you help me answer this question
r-ruslan [8.4K]
Division of a fraction is the equivalent of multiplying by its reciprocal
ex.
\frac{\frac{A}{B} }{\frac{C}{D}}=\frac{A}{B} *\frac{D}{C}
i suggest you try to remember this concept

in terms of your question

\frac{\frac{4c-12}{4c+8}}{\frac{c-3}{c^2-4}}= \frac{4c-12}{4c+8} *\frac{c^2 -4}{c-3}

from this point, just multiple the numerators together and denominators together, then simplify if necessary

fyi- difference of squares
x^2-b^2 = (x-b)(x+b)
relating that to
c^2-4 = c^2 -2^2 = (c-2)(c+2)

also a side note, you might want to factor out the 4 first in the top fraction


4 0
3 years ago
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