when you hit a chemical with hammer and it was frozen only its physical properties will change and not he chemical properties,
when heated it may decompose to other chemical
when you hit with hamer it physical appearance will change but it remains chemically the same
when you put in salt solution , it wil interact with ions and its chemical properties changes
similarly when it was frozen, it retains its chemical properties.
It is s<span>hutting down factories that discharge materials to rivers, </span>I am certain of it, because factors dump their waste in our waters, because they are a US Companies, and don't have the right to dump into international waters. Come on don't you remember any of that, companies dumping in our waters etc.
Answer
there are to answers one is an answer to a problem or a mixture of chemicals
Explanation:
The balanced equation is:
C3H8 + 5O2 > 3CO2 + 4H2O.
It takes 5 molecules of O2
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
First, let's convert 0.126 g of hydrogen to moles using its molar mass (2.02 g/mol).
Let's consider the steps to make alum (KAl(SO₄)₂⋅12H₂O) from aluminum (Al).
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2 Al(s) + 2 KOH(aq) + 6 H₂O(l) →2 KAl(OH)₄(aq) + 3 H₂(g)
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2 KAl(OH)₄(aq) + H₂SO₄(aq) → 2 Al(OH)₃(s) + K₂SO₄(aq) + 2 H₂O(l)
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2 Al(OH)₃(s) + H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 6 H₂O(l)
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K₂SO₄(aq) + Al₂(SO₄)₃(aq) + 24 H₂O(l) → 2 KAl(SO₄)₂⋅12H₂O(s)
To relate H₂ to KAl(SO₄)₂⋅12H₂O, we need to consider the appropriate molar ratios:
- In step 1, the molar ratio of H₂ to KAl(OH)₄ is 3:2.
- In step 2, the molar ratio of KAl(OH)₄ to Al(OH)₃ is 2:2.
- In step 3, the molar ratio of Al(OH)₃ to Al₂(SO₄)₃ is 2:1.
- In step 4, the molar ratio of Al₂(SO₄)₃ to KAl(SO₄)₂⋅12H₂O is 1:2.
The moles of KAl(SO₄)₂⋅12H₂O produced from 0.0624 moles of H₂ are:
The molar mass of alum is 474.38 g/mol. The mass corresponding to 0.0416 moles is:
Finally, we convert 19.7 grams to pounds using the conversion factor 1 lb = 454 g.
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
You can learn more about molar ratios here: brainly.com/question/15973092