Because they don’t have the same elements i guess, what is question 1?
Im not sure if this is the answer your looking for but hope you you find it helpful in a way! Thanks
Kinetic energy is energy in motion. Which of these isn't in motion?
A lady walking slowly but surely down a street is moving, right? So that isn't right.
A hockey puck sliding on ice has motion.
A man running around a track definitely demonstrates kinetic energy.
But, a baseball glove doesn't. Maybe if it's moving on someone's hand, but by itself, it isn't moving.
Exothermic reactions are chemical reactions that proceed with the release of heat energy. I contrast, endothermic reactions involve absorption of heat.
The enthalpy change (ΔH) for exothermic reactions is negative while that of endothermic reactions is positive.
In the given examples, reactions that show a negative ΔH are:
NH3 + HCl ------- NH4Cl ΔH = -176 KJ/mol
2Mg + O2 -------- 2MgO ΔH = -1203 kj/mol
C + O2 ---- CO2 ΔH = -393.5 kj/mol
CH4 + 2O2 ----------------- CO2 + 2H2O ΔH = -891 kj/mol
If we abbreviate the formula for nicotine as Nic, then the equations for two different equilibria of Nic in water are
Nic + H2O ---> NicH+ + OH-
NicH+ + H2O ---> NicH2 2+ + OH-
We can write the Kb1 expression for the first equation as
Kb1 = 1.0×10^-6 = [NicH+][OH-] / [Nic]
1.0×10^-6 = x^2 / 1.85×10^-3 - x
Approximating that x is negligible compared to 1.85×10^-3 simplifies the equation to
1.0×10^-6 = x^2 / 1.85×10^-3
x = 0.0000430
x = [OH-] = 4.30×10^-5 M
From the Kb2 expression
Kb2 = 1.3×10-11 = [NicH2 2+][OH-] / [NicH+]
1.1×10^-10 = x^2 / 4.30×10^-5 - x
Approximating that x is negligible compared to 4.30×10^-5 simplifies the equation to
1.1×10^-10 = x^2 / 4.30×10^-5
x = [OH-] = 6.88×10^-8
The concentration [OH-] can be computed as
[OH-] = 4.30×10^-5 M + 6.88×10^-8 M = 4.30×10^-5 M
This shows that the second equilibrium has a negligible effect on the pH.
We can now calculate for pH:
pOH = -log [OH-] = -log (4.30×10^-5 M) = 4.37
pH = 14 - pOH = 14 - 4.37 = 9.63