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HACTEHA [7]
2 years ago
11

What is the missing part​

Mathematics
2 answers:
mihalych1998 [28]2 years ago
5 0

Answer: the missing part is 45

suppose:  the missing part is x

we use Thales theorem:

\frac{x}{18}=\frac{20}{8}\\\\=> x = \frac{20.18}{8}=45

Step-by-step explanation:

Roman55 [17]2 years ago
4 0

use thales theorem to solve this question

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The length of a classroom is 34 feet. What is the measurement in yards and feet?
Bezzdna [24]
The first thing you would do is divide 34 by 3, which is how many feet are in a yard, After you get your quotient, you will have a remainder, which will be your feet! Let me know if you have any questions!
8 0
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Calculus graph please help
tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

Part A)

<em>f</em> is increasing whenever <em>f'</em> is positive and decreasing whenever <em>f'</em> is negative.

Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

And <em>f</em> is decreasing for the interval:

\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

Hence, <em>f</em> has relative maximums at <em>x</em> = -2 and <em>x</em> = 1, and relative minimums at <em>x</em> = -1 and <em>x</em> = 3.

Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

Hence, <em>f</em> is concave up for the interval (rounded to the nearest tenths):

\displaystyle (-1.5 , 0) \cup (2.2, \infty)

And concave down for the interval:

\displaystyle (-\infty, -1.5) \cup (0, 2.2)

Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

In other words, <em>f </em>has an inflection point wherever <em>f'</em> has an extremum point.

<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

7 0
2 years ago
Consider the function f(x)=x(x-4).
alexandr402 [8]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Choose all the expressions that are equal to 5/9×8. A. 9÷5×8 B. 8/9×5 C. 5÷8×9 D. 5×1/9×8 E. 5×8
Charra [1.4K]
<h2>Problem:</h2>

Choose all the expressions that are equal to 5/9×8.

A. 9÷5×8

B. 8/9×5

C. 5÷8×9

D. 5×1/9×8

E. 5×8

<h2>Solution:</h2>

\purple{ \frac{5}{9}  \times 8 =  \frac{40}{9}  = 4 \:  \frac{4}{9} }

\red{9 \div 5 \times 8 =  \frac{9}{5}  \times 8 =  \frac{72}{5}  = 14 \:  \frac{2}{5} }

\red{ \frac{8}{9}  \times 5 =  \frac{40}{9}  =  \boxed{4 \:  \frac{4}{9} }}

\red{5 \div 8 \times 9 =  \frac{5}{8}  \times 9 =  \frac{45}{8}  = 5 \:  \frac{5}{8} }

\red{5 \times  \frac{1}{9}  \times 8 =  \frac{5}{9}  \times 8 =  \frac{40}{9}  =  \boxed{4 \:  \frac{4}{9} }}

\red{5 \times 8 = 40}

<h2>Answer:</h2>

<u>B</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>D</u>

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
5 0
3 years ago
6. Enuanuel was speaking with a friend from another country. His friend told
Kaylis [27]
I believe 62 because it it’s closer to an hour
5 0
3 years ago
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