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2 years ago

A cell phone is on sale for 30% off. If the sale price is $239.89, what is the original price? *

Mathematics

2 answers:

irakobra [83]2 years ago

5 0

AnswerThe answer is $167.92

Step-by-step explanation:30% is equivalent to 0.3. Subtract 0.3 from $239.89. You have answer plz mark brainliest.

IrinaK [193]2 years ago

4 0

The answer is $342.70
Explanation: we are looking for an ORIGINAL price so it would be more than the sale price.

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Calculating area of rectangle.

Artemon [7]

Answer:

Your measurements; Area = 216.108 cm²

Another student's measurements; Area = 216.9404 cm²

- Difference in area could be as a result of human error or perhaps that they made use of different measuring tools.

Step-by-step explanation:

For Your measurements;

Length of rectangle = 20.70 cm

Width of rectangle = 10.44 cm

Area of rectangle is given by; A = length × width = 20.7 × 10.44 = 216.108 cm²

For Another student's measurements;

Length of rectangle = 20.74 cm

Width of rectangle = 10.46 cm

Area = 20.74 × 10.46

Area = 216.9404 cm²

The areas they both obtained are not of equal values and this could be as a result of human error or perhaps that they used different measuring tools.

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3 years ago

Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

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3 years ago

Misaki cut some wood for a bookcase she is building.She needs to find how many 1

den301095 [7]

Answer:

3ft + 2ft?

Step-by-step explanation:

sorry i would take this with a bucket of salt its prob not c0rr3t

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2 years ago

What is the meaning of life, the universe, and everything?

disa [49]

Answer:

meaning of life is life

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2 years ago

Read 2 more answers

Select all the correct answers.

sukhopar [10]

Answer:

Second point (-5/2, -7/2)

First point (3/2, 17/2)

Step-by-step explanation:

We have two equations, and we want to know at wich poin are equal. Hence, we have a system of equations and the solution is nothing more that the point (x,y) where those functions intercepts.

4x2+ 7x -11=y

3x+4=y

Lets use substitute method

4x2+7x-11=3x+4

This can be re arrange as the following eq:

4x2+4x-15=0

A quadratic equation, its solution can be obtained using the below eq.

$x=\frac{-b+/- \sqrt{x^{2}-4ac } }{2a}$

where a=4, b=4, c=-15.

Remember, the quadratic equation as a +/- sign, meaning that you will obtain one answer using the + operator and other using the - operator.

By doing the above, we have x=-5/2 and x=3/2

By using x=3/2 in equation of line (3x+4=y) we have y=17/2

First point (3/2, 17/2)

By using x=-5/2 in equation of line (3x+4=y) we have y= -7/2

Second point (-5/2, -7/2)

Those points are the ones where the line and the parabola intercept.

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3 years ago