Answer:
7x-2, -x-6y+16, 5x-3
Step-by-step explanation:
I'm guessing the three expressions are:
1. 3(x+2) + 4(x-2)
2. 2(x+y) - 3(x+y) - (y+8) + 4(6-y)
3. 2(4x+3) - 3(x+1)
... 1. 3(x+2) + 4(x-2)
= 3x + 6 + 4x - 8
= 7x - 2
... 2. 2(x+y) - 3(x+y) - (y+8) + 4(6-y)
= 2x + 2y - 3x - 3y - y - 8 + 24 - 4y
= -x - 6y + 16
... 3. 2(4x+3) - 3(x+1)
= 8x + 6 - 3x - 3
= 5x - 3
Answer:
-2 ft/min
Step-by-step explanation:
If Kim dropped for a total of 8 feet over the course of 4 minutes, then 8 feet/4 min equals 2 ft/min, but because they are dropping it should be negative.
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
