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Snowcat [4.5K]
3 years ago
7

a water spinkler sends water out in a circular pattern how large is the watered area if the watering pattern is 12 ft

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

The number of feet away from the sprinkler where it could spread water would be the radius of the circle in which it is spraying.

The Area of a circle is

πr2=808.64

(3.14)r2=808.64

Divide both sides by 3.14

r2=257.5286624

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It's 48,169 x 10^5
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How do you write 527,519 in expanded from using exponents
Aleksandr-060686 [28]
527,519

= 500,000 + 20,000 + 7,000 + 500 + 10 + 9

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What is 10 - 4 and 2/3?
Ymorist [56]
10 - 4 2/3

First, we convert mixed fraction into improper fraction.

4 2/3 = ((4*3)+2)/3 = 14/3

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8 0
3 years ago
A random sample of 200 voters in a town is selected, and 114 are found to support an annexa- tion suit. Find the 96% confidence
EastWind [94]

Answer:

a) 96% CI: 0.51\leq\pi\leq 0.63

b) If we estimate that the fraction of voters is 0.57, we can claim with 96% confidence that the error is equal or less than 0.06 from the estimated proportion.

Step-by-step explanation:

The proportion of the sample is

p=\frac{114}{200}=0.57

The standard deviation of the sample proportion is

\sigma=\sqrt{\frac{p(1-p)}{n} } =\sqrt{\frac{0.57(1-0.57)}{200} } =\sqrt{\frac{0.2451}{200} } =0.035

For a 96% CI, the z-value is z=1.751.

Then, the 96% CI can be written as:

p-z\cdot \sigma\leq\pi\leq p+z\cdot \sigma\\\\0.57-1.751*0.035\leq\pi\leq 0.57+1.751*0.035\\\\0.57-0.06\leq\pi\leq 0.57+0.06\\\\0.51\leq\pi\leq 0.63

b) If we estimate that the fraction of voters is 0.57, we can claim with 96% confidence that the error is equal or less than 0.06 from the estimated proportion.

6 0
4 years ago
In a random sample of 25 ​people, the mean commute time to work was 33.9 minutes and the standard deviation was 7.2 minutes. Ass
Phoenix [80]

Answer:

33.9-1.32\frac{7.2}{\sqrt{25}}=31.999    

33.9+1.32\frac{7.2}{\sqrt{25}}=35.801    

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}}

And replacing we got:

ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=33.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=7.2 represent the sample standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=25-1=24

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,24)".And we see that t_{\alpha/2}=1.32

Now we have everything in order to replace into formula (1):

33.9-1.32\frac{7.2}{\sqrt{25}}=31.999    

33.9+1.32\frac{7.2}{\sqrt{25}}=35.801    

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}}

And replacing we got:

ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008

   

7 0
4 years ago
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