We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
100-75=25% did not like
25%=35 students how about 75%
75 x 35 divided by 25=105 students
105
B. No, because it fails the vertical line test.
Answer:
The bottom right histogram is the correct one.
Step-by-step explanation:
Carrots weight 40-49 kg = 2
... of weight 50-59 = 6
... of weight 60-69 = 4
.. of weight 70-79 = 1
The set of equation that is known to have 5 and 0 as solutions is A and B.
<h3>How to solve for the system of equations.</h3>
From the graph that we have here in this question, we are supposed to identify the equations that have this point.
We can do this by tracing the lines in order to locate 5 and 0 on the grid.
When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.
Read more on graphs here:
brainly.com/question/10465970
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