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Karo-lina-s [1.5K]

2 years ago

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Hey are using WordPress for your blog platform? I'm new to the blog world but I'm trying to get started and set up my own. Do yo

u require any coding knowledge to make your own blog? Any help would be really appreciated! Bcedkkkgfgee

1 answer:

Inga [223]2 years ago

7 0

Can you gimme 10 points

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Can anyone please help FAST! I’m looking for the correct answer and how you explain it! I’ll mark brainlist please and thank you

rosijanka [135]

1a. Y = mx + b
Y = 2x + b
-2 = 2(5) + b
-2 = 10 + b, b = 12
Equation: y = 2x + 12

1b. Standard form: Ax + By = C
subtract 12 and y from both sides
2x - y = -12
Equation: 2x - y = -12

7 0

2 years ago

Read 2 more answers

Graph the function f(x) = -42-4+ 5 on the axes below. You must plot the

valentina_108 [34]

Answer:

- attached graph

- Horizontal Asymptote: y = 5

- twon whole number points are (4,4) and (5,1)

Step-by-step explanation:

- Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote

y = -4^(x-4) + 5

= -4^(4-4) + 5

= -4^(0) + 5

= -1 + 5

= 4

y = -4^(x-4) + 5

= -4^(5-4) + 5

= -4^(1) + 5

= -4 + 5

= 1

7 0

1 year ago

The total number of markers that Nancy has if she gives away 2/5 of her m markers to Amy

Archy [21]

Answer:

she has 3/5 left

7 0

3 years ago

Read 2 more answers

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size 'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size n₂ = 24</em>

<em>mean of the second sample "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample S₂ = 2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em> </em> $t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

<em> where </em> $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

<em> substitute values and we get S² = 40.988</em>

<em> </em> $t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$ <em></em>

<em> </em> t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em> </em>

<em> </em>

<em> </em>

6 0

2 years ago

Please answer the question in the picture below

Elanso [62]

The answer is b because there is a negative in the exponent and the number needs to be a single digit and 54 is double digit. hope this helps!

5 0

3 years ago