Mrs. Virtueson has 1/4 of a pecan pie. She wants to give half

Mathematics

2 answers:

cricket20 [7]3 years ago

6 0

Answer:

What fractional part of a pie will each get

each will get 1/8

elena55 [62]3 years ago

6 0

Each gets 1/8th of the pie

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PLEASE HELP ME WITH IT.

scoundrel [369]

OK. I did it. Now let's see if I can go through it without
getting too complicated.

I think the key to the whole thing is this fact:

 A radius drawn perpendicular to a chord bisects the chord.

That tells us several things:

-- OM bisects AB.
 'M' is the midpoint of AB.
 AM is half of AB.

-- ON bisects AC.
'N' is the midpoint of AC.
 AN is half of AC.

-- Since AC is half of AB,
 AN is half of AM.
 a = b/2

Now look at the right triangle inside the rectangle.
'r' is the hypotenuse, so

 a² + b² = r²

But a = b/2, so (b/2)² + b² = r²

(b/2)² = b²/4 b²/4 + b² = r²

Multiply each side by 4: b² + 4b² = 4r²
 - - - - - - - - - - -
 0 + 5b² = 4r²
Repeat the
original equation: a² + b² = r²

Subtract the last
two equations: -a² + 4b² = 3r²

Add a² to each side: 4b² = a² + 3r² . <=== ! ! !

7 0

3 years ago

Tell me something to watch your girl do be bored...

Fittoniya [83]

Answer:

ᴡᴀᴛᴄʜ sᴏᴍᴇ ᴍᴜsɪᴄ ᴠɪᴅᴇᴏs...ᵗʰᵃᵗ ⁱˢ ʷʰᵃᵗ ⁱ ʷᵃᵗᶜʰ ʷʰᵉⁿ ⁱ ᵍᵉᵗ ᵇᵒʳᵉᵈ...ᵐᵒˢᵗˡʸ ᵏᵖᵒᵖ

<h2>ᴋᴅʀᴀᴍᴀ ʟɪsᴛ ᵐʸ ᶠᵃᵛˢ :</h2>

ʜᴏᴛᴇʟ ᴅᴇʟ ʟᴜɴᴀ

ɪᴛ ɪs ᴏᴋᴀʏ ᴛᴏ ɴᴏᴛ ʙᴇ ᴏᴋᴀʏ

ʜᴡᴀʀᴀɴɢ

ᴄʀᴀsʜ ʟᴀɴᴅɪɴɢ ᴡɪᴛʜ ʏᴏᴜ

ᴘᴇɴᴛʜᴏᴜsᴇ

$\infty \infty$

8 0

2 years ago

Explain why a geometric series with a ratio between zero and one converges and how you find the sum.

Alex Ar [27]

Let $S_n$ be the $n$ th partial sum of a geometric sequence with common ratio $r$ and first term $a$ . So the sequence is $\{a,ar,ar^2,\cdots\}$ , and $S_n$ is

$S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}$

Multiplying both sides by $r$ gives

$rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n$

and subtracting $rS_n$ from $S_n$ gives

$S_n-rS_n=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n$
$(1-r)S_n=a(1-r^n)$
$S_n=a\dfrac{1-r^n}{1-r}$

If $0$ , then $r^n\to0$ as $n\to\infty$ and so the sum approaches

$\displaystyle\lim_{n\to\infty}S_n=\dfrac a{1-r}$