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3 years ago

Helpppp Quickk!!! Solve the following ewuation: 3x=-12

Mathematics

2 answers:

lesya692 [45]3 years ago

5 0

Answer:

$3 {x}^{2} = - 12 \\ {x}^{2} = - 12 \div 3 \\ {x}^{2} = - 4 \\ x = \sqrt{ - 4 } \\ x = \frac{ + }{} 2$

Option D, hope it helps!

Korvikt [17]3 years ago

4 0

Answer:x=-2

Step-by-step explanation:

3 x -2^2

3 x -4 = -12

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Please help me with this

Ipatiy [6.2K]

Answer:

(-4,1) because if the x value repeats the relation is no longer a function

7 0

2 years ago

Read 2 more answers

Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a

Aliun [14]

Answer:

70 groups

Step-by-step explanation:

$5c_{3}*7c_{1}$

$=\frac{5*4*3}{3*2*1} *\frac{7}{1} \\=70$

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3 years ago

How many grams of 0.5% hydrocortisone cream must be mixed with 180 g of 2.5 % cream to make a 1 % w/w hydrocortisone cream? HINT

Sophie [7]

Answer:

We need 540 grams of 0.5% hydrocortisone cream

Step-by-step explanation:

Lets call x the amount of grams needed. This means that the combined cream will have 180+x grams. We want x such that

x * 0.005 + 180*0.025 = (180+x)*0.01

Hence

0.005x + 4.5 = 1,8+0.01x

Lets put the x in the same side and take common factor

4.5-1.8 = 0.01x-0.005x

2.7 = (0.01-0.005)x = 0.005x

As a result

x = 2.7*0.005 = 540

We need 540 grams.

3 0

3 years ago

Do well-rounded people get fewer colds?

asambeis [7]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.

For this, a sample of 276 healthy men and women was taken.

n₁= 96 had few social outlets

n₂= 105 had six or more activities

These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:

p'₁= 0.62 (62% of the people with few social outlets got sick)

p'₂= 0.35 (35% of the people with six or more activities got sick)

The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.

You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂

(p'₁ - p'₂) ± $Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }$

$Z_{1-\alpha /2}= Z_{0.995}= 2.586$

(0.62-0.35) ± 2.586 $\sqrt{\frac{0.62*0.38}{96} +\frac{0.35*0.65}{105} }$

[0.094; 0.045]

With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.

I hope it helps!

8 0

2 years ago

What would x equal for these two? 15/24 = x/3 & 7/24 = 3/x Thank you!!!

vesna_86 [32]

The first one you have $\frac{15}{24}$ = $\frac{x}{3}$ . To solve this you would multiply both sides by 3.