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3 years ago

6

Plz helps so i can pass

1 answer:

nasty-shy [4]3 years ago

4 0

Answer:

C

Step-by-step explanation:

did it on edge

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What is the value of x

aivan3 [116]

Answer:

x=14√3 and y=28

Step-by-step explanation:

This is a 30, 60, 90 triangle. We have to multiply 14 by 2 to get the hypotenuse. In this case, the hypotenuse is y. 14x2 is equal to 28. Therefore, y=18. The long side is equal to the small side times the √3. Therefore, x is equal to 14√3. Therefore, x=14√3 and y=28.

If this has helped you please mark as brainliest

4 0

3 years ago

Jesses team won the basketball game, scoring 96 points. The other team only scored 71 points. Jesse scores 16 of those points, a

Dovator [93]

Answer:

7

Step-by-step explanation:

71-16=56/8=7 number of points

3 0

3 years ago

A storage container in the form of a rectangular prism is measured to be 12 inches by 8 inches

adelina 88 [10]

The measured volume is 12*8*4=382. The actual measurement volume is 11.75*7.75*4=364.25. The relative error is (382-364.25)/364.35=0.049.

7 0

3 years ago

If you have 1,000,000 $ and you stend 9,899 what does that =

allsm [11]

If you have 1,000,000 $ and you spend 9,899 what does that =

1,000,000 - 9,899 = 990,101

Answer: $990,101

3 0

3 years ago

Read 2 more answers

How do you determine the area under a curve in calculus using integrals or the limit definition of integrals?

RSB [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Let us consider

$y = f(x)$

To find the area under the curve $y = f(x)$ between $x = a$ and $x = b$ , all we need is to integrate $y = f(x)$ between the limits of $a$ and $b$ .

For example, the area between the curve y = x² - 4 and the x-axis on an interval [2, -2] can be calculated as:

$A=\int _a^b|f\left(x\right)|dx$

= $\int _{-2}^2\left|x^2-4\right|dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=\int _{-2}^2x^2dx-\int _{-2}^24dx$

solving

$\int _{-2}^2x^2dx$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=\left[\frac{x^{2+1}}{2+1}\right]^2_{-2}$

$=\left[\frac{x^3}{3}\right]^2_{-2}$

computing the boundaries

$=\frac{16}{3}$

Thus,

$\int _{-2}^2x^2dx=\frac{16}{3}$

similarly solving

$\int _{-2}^24dx$

$\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax$

$=\left[4x\right]^2_{-2}$

computing the boundaries

$=16$

Thus,

$\int _{-2}^24dx=16$

Therefore, the expression becomes

$A=\int _a^b|f\left(x\right)|dx=\int _{-2}^2x^2dx-\int _{-2}^24dx$

$=\frac{16}{3}-16$

$=-\frac{32}{3}$

$=-10.67$ square units

Thus, the area under a curve is -10.67 square units

The area is negative because it is below the x-axis. Please check the attached figure.

6 0

3 years ago