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2 years ago

PLEASE HELP ASAP MUCH APPRECIATED.

Mathematics

2 answers:

posledela2 years ago

8 0

I don't know how to explain part C... sorry

vlada-n [284]2 years ago

6 0

Whats The question i will help you answer

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Miriam and Ruth are each individually applying for an $8,000, 24-month personal

IgorC [24]

Answer:

Miriam

Step-by-step explanation:

Miriam, with her lower FICO score, is more likely to have been offered the loan with the higher interest rate.

3 0

3 years ago

Which function has x-intercepts of 3 and 8 and contains the point (–1, –2)?

mojhsa [17]

This is how you do it.

y = a(x - 3)(x - 8)
-2 = a(-1 - 3)(-1 - 8) 
-2 = 36a 
- 1 / 18 = a 
y = ( - 1 / 18)(x^2 - 11x + 24) 
y = (- 1 / 18)x^2 + (11 / 18)x - (3 / 2)

If this doesn't explain it enough, please, ask questions.

6 0

3 years ago

Covert 298.4 to a fraction

Kruka [31]

$\\ \sf\longmapsto 298.4$

$\\ \sf\longmapsto \dfrac{2984}{10}$

$\\ \sf\longmapsto \dfrac{1492}{5}$

7 0

2 years ago

Read 2 more answers

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago

Write down a fraction whose value lies between 3 and 4; whose denominator is a multiple of 5; whose numerator is a multiple of 1

slamgirl [31]

Answer:

33/10 and 55/15

Step-by-step explanation:

Possible denominators that are multiples of 5 less than 17 are 5, 10, 15.

Corresponding numerator ranges are [15, 20], [30, 40], and [45, 60]. In only two of these ranges are there any multiples of 11.

33 in [30, 40]

55 in [45, 60]

So, there are only two possible fractions meeting your requirement:

33/10 and 55/15

6 0

3 years ago