Answer:
A exterior angle of a polygon is an angle outside the polygon formed by one of its sides and the extension of an adjacent side.
Angle A: 60 degrees
Angle B: 30 degrees
Angle C: 90 degrees
Answer:
w = (cv +dy) / (cb - ad)
Step-by-step explanation:
Multiply through by c
aw + y = c(bw + v) / d Multiply by d
d(aw + y) = c(bw + v) Remove the brackets
daw + dy = cbw + cv Subtract dy from both sides.
daw +dy - dy = cbw + cv -dy
daw = cbw + cv - dy Subtract cbw from both sides
daw - cbw = cbw - cbw + cv - dy
daw - cbw = cv - dy Isolate W on the left.
w(da - cb) = cv - dy Divide by cb - ad on both sides.
w = (cv - dy) / (ad - bc) Answer
You should first find out what lines are what,
Like for example, If you had 5 - 10 - 15 as the Y Lines and the bar was between 5 and 10 then your best bet would be to estimate what the middle of 5 and 10 is which would be 7 or 8.
