To solve the trigonometric expression we proceed as follows;
7(tan x)^3-21tanx=0
this can be written as:
7(tan x)^3=21tanx
dividing through by 7 we get:
(tan x)^3=tan x
dividing through by tan x we get:
(tanx)^1=1
hence;
tan x=+\-1
when tan x=1
x=45
when tan x=-1
x=-45
Given that our answer should be at the interval [0,2π] the answer:
45=45/180=1/4π
The correct answer is D.
Have a great day!
(x + 6)/2 - (x - 8)/3 = 5
Multiply each term by 6:-
3(x + 6) - 2(x - 8) = 30
3x + 18 - 2x + 16 = 30
3x - 2x = 30 -18 - 16
x = 30 - 34
x = -4 (answer)
Answer:
<h3><u>Cylinder</u></h3>

Given:

<h3><u>Cube</u></h3>

Given:

<h3><u>Volume available to be filled with water</u></h3>
Volume of cylinder - volume of cube
= 684π - 512
= 1532.75204 cm³
1 litre = 1000 cm³
⇒ 1.5 litres = 1000 × 1.5 = 1500 cm³
As 1500 < 1532.75204, the volume of water poured into the container is smaller than the empty space available in the cylinder. Therefore, the water will <u>not</u> come over the top of the container.
Answer:B)The values of both x and y will be real numbers greater than or equal to 0.
Step-by-step explanation: