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Ira Lisetskai [31]
3 years ago
12

Select the correct answer.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0
The answer is D could you give me brainlist
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Suppose monthly rental prices for a one-bedroom apartment in a large city has a distribution that is skewed to the right with a
omeli [17]

Answer:

a) Nothing, beause the distribution of the monthly rental prices are not normal.

b) 1.43% probability that the sample mean rent price will be greater than $900

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

(a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930?

Nothing, beause the distribution of the monthly rental prices are not normal.

(b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?

Now we can apply the Central Limit Theorem.

\mu = 880, \sigma = 50, n = 30, s = \frac{50}{\sqrt{30}} = 9.1287

This probability is 1 subtracted by the pvalue of Z when X = 900.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{900 - 880}{9.1287}

Z = 2.19

Z = 2.19 has a pvalue of 0.9857

1 - 0.9857 = 0.0143

1.43% probability that the sample mean rent price will be greater than $900

8 0
3 years ago
Line segment CD is shown on a coordinate grid:
Lady_Fox [76]

Answer:

im pretty sure the answer would be C'D' and CD would be equal in length!

Step-by-step explanation:

because you are only reflecting it across the y-axis, no changes will be made to the line itself, only the location of the line :)

7 0
3 years ago
Read 2 more answers
F(1) = 5
MatroZZZ [7]

Answer:

a(7)=3645

Step-by-step explanation:

you have :

f(1) =a= 5

and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)

So r=3

then

a(n)=a*r^(n-1)

a(7)=5*3^(7-1)

a(7)=5*3^6=3645

<em>hope this helps</em>

<em />

7 0
2 years ago
3/5 ÷ 1 1/4 =<br> (20 points)
Anna11 [10]

3/5 ÷ 1 1/4 = 0.48

0.48 will be your anwer


7 0
3 years ago
Color blindness is an inherited characteristic that is more common in males than in females. If M represents male and C represen
DerKrebs [107]

Answer:

The probability that a randomly selected person is not color blind is 0.958

Step-by-step explanation:

Given,

C represents red-green color blindness,

Also, the probability that a randomly selected person is color blind,

P(C) = 0.042,

Thus, probability that a randomly selected person is not color blind,

P(C') = 1 - P(C) = 1 - 0.042 = 0.958

4 0
3 years ago
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