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3 years ago

Select the correct answer.

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

The answer is D could you give me brainlist

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127 3/4 miles is 35% of what number of miles?

ale4655 [162]

Answer:

It is the 35% percent of 365 miles.

Step-by-step explanation:

Use formula,

35%*x=127 3/4

4 0

3 years ago

Find the volume of the following figure. 890 units 3 900 units 910 units 3 882 units3

ludmilkaskok [199]

The answer in 766units^2

4 0

3 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

3 years ago

according to school records 15% of kids or left-handed there are a total of 218 students in kindergarten in 209 students and fir

Alex17521 [72]

218 + 209 = 427

427 *.15 =64.05 so 64

8 0

3 years ago

You and your friend are having a race, but since you are faster than him, you decide to give him a head start. He starts 10m in

Diano4ka-milaya [45]

Answer:

20 seconds

Step-by-step explanation:

Your friend starts 10 meters in front of the starting line.

You start from the starting line.

You run at 6 meters/ second.

Your friend runs at 5.5 meters/second.

You and your friend will be at the same distance from the starting line only when you are able to catch your friend.

The relative speed between you two is the difference in your speed and your friend's speed that is:

$6-5.5=0.5m/s$

So to cover 10 meters of separation at the speed of 0.5 meter/second it will take:

$t=\frac{10}{0.5}= \frac{100}{5}=20s$

So it will take 20 seconds for you and your friend to be at the same distance from the starting line.

8 0

3 years ago

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