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jeka94
3 years ago
6

Suppose one wishes to accelerate a 2000 kg Toyota from 10 m/s 30 m/s in 8 seconds. What force would be required?

Physics
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

5000 N

Explanation:

F = m×Δv/Δt

F = 2000(30-10/8)

F = 5000 N

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I NEED HELP ASAPPPP!!
Juli2301 [7.4K]

Increase in wavelength will cause decrease in frequency. When wavelength doubles, the frequency of the wave will reduce to half of its value.

<h3>WAVE SPEED</h3>

The wave speed is the product of wave frequency and its wavelength.

v = f⋅λ

  • v = the speed of a wave
  • f = frequency
  • λ = wavelength

For example, if a wave has a frequency of 120 Hz and a wavelength of 5m, it would have a speed of 600 m/s.

if the wavelength is increased to 10m but the speed stays the same at 600 m/s. That is,

λ = 10m

v = 600 m/s

v = f⋅λ

Substitute f and v into the formula

600 = 10f

f = 600 / 10

f = 60 m

The frequency of the wave is reduced to half of its value.

Learn more about wave speed here: brainly.com/question/2847127

8 0
2 years ago
During what intervals was jenny negatively accelerating
PolarNik [594]

Jenny's acceleration was negative during the intervals of time when her speed was decreasing.

That's really all we can tell, because you really haven't given us any information except her name.

5 0
4 years ago
Rocks are classified as sedimentary igneous or metamorphic primarily based upon differences in their
yanalaym [24]
The differences in their formations. Igneous is formed by cooled and crystallized rock, sedimentary is formed by sediment compaction and cementation, and metamorphic is formed by intense heat and pressure.
3 0
2 years ago
Read 2 more answers
True or false total distance of amoving body can be negative​
Charra [1.4K]

Answer:

False

Explanation:

the total distance of a moving body is always positive

Distance is the total distance between any two points

8 0
3 years ago
In figure 1, charge q2 experiences no net electric force. What is q1?
lukranit [14]

By using Coulomb's law, we want to find the value of q₁ given that q₂ experiences no net electric force. We will find that q₁ = 8nC

<h3>Working with Coulomb's law.</h3>

Coulomb's law says that for two charges q₁ and q₂ separated by a distance r, the force that each one experiences is:

F = k\frac{q_1*q_2}{r^2}

Where k is a constant

Here we can see that q₂ interacts with two charges, then the total force on q₂ will be:

F = k\frac{q_1*q_2}{(20cm)^2} + k\frac{-2nC*q_2}{(10cm)^2}

And we know that it must be equal to zero, so we can write it as:

F = k\frac{q_1*q_2}{(20cm)^2} + k\frac{-2nC*q_2}{(10cm)^2} = 0\\\\k*q_2*(\frac{q_1}{(20cm)^2} + \frac{-2nC}{(10cm)^2}) = 0\\

The parenthesis must be equal to zero, so we can write:

\frac{q_1}{(20cm)^2} + \frac{-2nC}{(10cm)^2} = 0

And now we can solve this for q₁ to get:

q_1  = 2nC*(\frac{(20cm)^2}{(10cm)^2} ) = 8nC

If you want to learn more about Coulomb's law, you can read:

brainly.com/question/24743340

3 0
3 years ago
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