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Ber [7]
2 years ago
8

Show that the input and output work done by the pistons is the same during "Pascal's principle" derivation

Physics
2 answers:
JulijaS [17]2 years ago
6 0

Answer:

I dint no is the answer of the puatinfn

olasank [31]2 years ago
3 0

Answer:

so b=2.8×105pa

Explanation:

here is your answer Hope you will enjoy and mark me as brainlist

thank you

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A 5kg rock is lifted 2m. Find the amount of work done. ​
lianna [129]

Answer:

98J

Explanation:

Given parameters:

Mass of rock  = 5kg

Height = 2m

Unknown:

Work done  = ?

Solution:

The amount of work done is given as:

 Work done  = Force x distance

 Work done = Weight x height

  Work done  = mgH

Now insert the parameters and solve;

 Work done  = 5 x 9.8 x 2 = 98J

5 0
3 years ago
HELP ASAP!!!!! ILL MARK YOU BRAINLIEST!
Julli [10]
Hello! Sorry this is a little late!

The answer to your question would best be option C, y<span>es, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

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8 0
3 years ago
Read 2 more answers
What two gases probably dominated precambrian earth's atmosphere?
galben [10]
I think these gases are water vapor and nitrogen. As the temperature rises, these water vapor molecules, would condense and form the oceans we have. Also, it was said that in the early atmosphere, nitrogen is very abundant and even today the composition of air is 79% by volume.
8 0
3 years ago
The nutritional label above came from a can of soup how many servings of soup would you need to eat to receive your recommended
Flauer [41]
Each serving gives 3 grams or 12% of daily recommended value. Divide 100% by 12% to get 8.33 servings to obtain the daily recommended value of 25 grams.
3 0
3 years ago
Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe
deff fn [24]

Answer:

\theta_2 - \theta_1 = 156.93 degree

Explanation:

As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude

so we have

y = A sin\omega t

y = \frac{A}{5}

so now we have

\frac{A}{5} = A sin\omega t

now we have

\theta_1 = 11.53 degree

so the phase other particle in opposite direction is given as

\theta_2 = 180 - 11.53 = 168.46 degree

so we have phase difference given as

\theta_2 - \theta_1 = 168.46 - 11.53

\theta_2 - \theta_1 = 156.93 degree

7 0
3 years ago
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