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Vanyuwa [196]
2 years ago
9

You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 13-m-hi

gh hill, then descends 20 m to the track's lowest point. You've determined that the spring can be compressed a maximum of 2.4 m and that a loaded car will have a maximum mass of 430 kg. For safety reasons, the spring constant should be 13 % larger than the minimum needed for the car to just make it over the top. Part A What spring constant should you specify
Physics
1 answer:
Andrew [12]2 years ago
3 0

Answer:

22.15 N/m

Explanation:

As we know potential energy = m*g*h

Potential energy of spring = (1/2)kx^2

m*g*h = (1/2)kx^2

Substituting the given values, we get -  

(400)*(9.8)*(10) = (0.5)*(k)*(2.0^2)

k = 39200/2.645

k = 19600 N/m

For safety reasons, this spring constant is increased by 13 % So the new spring constant is  

 k = 19600 * 1.13 = 22148 N/m = 22.15 N/m

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Answer:

a) the required time is 0.6283 μs

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we substitute

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25V =  25V × sin( 2.5 × 10⁶ s⁻¹ × t )

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sin( 2.5 × 10⁶ × t ) = 1

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b) What is the inductor current at that time?

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{ sin(ωt) = 1 )

I(t) = V₀√(C/L)

we substitute

I(t) = 25V × √( ( 8.0 × 10⁻¹² F ) / ( 20 × 10⁻³ H ) )

I(t) = 25 × 0.00002

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