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2 years ago

Find the difference (d - 9) - (3d - 1)

Mathematics

1 answer:

Neko [114]2 years ago

7 0

Answer:

-2d-8

Step-by-step explanation:

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25 POINTS -4(x+2) Plz help asap

timofeeve [1]

Answer:

$- 4x - 8$

Step-by-step explanation:

$- 4(x + 2) = - 4x - 8$

Hope this helps ;) ❤❤❤

7 0

2 years ago

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Evaluate g(x)=6x when x=-3,0, and 4 .

hram777 [196]

Answer:

-3 = -18

0 = 0

4 = 24

Step-by-step explanation:

-3... so 6(-3) equals -18 because a positive times a negative equals a negative

0... so 6 (0) equals 0 because anything multiplied by 0 equals 0

4... so 6 (4) equals 24

() means multiplied by so if it’s y(x) then that means y is multiplied by x :)

3 0

2 years ago

Aaron rides his bike at a constant rate of 10 miles per hour. Which table represents y, the number of miles Aaron rides his bike

Tema [17]

Answer:

I believe the answer is c. but I'm not too sure.

Step-by-step explanation:

my reasoning for this is because it's the chart that is constant. y starts out with 5=0.5 & they add five more on y's side. & x increased the same amount throughout the chart.

5 0

2 years ago

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A construction worker earns 2880 in 6 days. If he earns 8640 in a month, for how

V125BC [204]

Step-by-step explanation:

2880x3=8640

6x3=18

he worked 18 days.

6 0

2 years ago

The rectangle below has an area of 70y⁸ 30y⁶. The width of the rectangle is equal to the greatest common monomial factor of 70y⁸

Lorico [155]

Answer:

The Width of the Rectangle = $10y^6$

$\text{Length of the Rectangle}=210y^8$

Step-by-step explanation:

The area of the rectangle $=70y^8 30y^6.$

We are told that the width of the rectangle is equal to the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Let us determine the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Express each term as a product to pick out the common factors:

$70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6$

In the two terms, the common terms are 10 and $y^6$ . Therefore their greatest monomial factor = $10y^6$

The Width of the Rectangle = $10y^6$

Recall: Area of a Rectangle =Length X Width

$70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8$

6 0

2 years ago

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