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daser333 [38]
3 years ago
7

Find the difference (d - 9) - (3d - 1)

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

-2d-8

Step-by-step explanation:

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Find the first four terms of the infinite sequence defined explicitly by the following rule.
Nataly_w [17]
The only thing that you should do is to put 1, 2, 3, and 4 instead of the n and then you will get the first four terms! 

f(1) = 4(1) - 2 = 2 
f(2) = 4(2) - 2 = 6
f(3) = 4(3) - 2 = 10 
f(4) = 4(4) - 2 =  14 

Have a great day! 
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Which set(s) of points show x in DIRECT PROPORTION to y? A) {E, C, B} only B) {G, C, A} only C) {F, E, D} and {E, C, B} only D)
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Answer:{F, G, H} and {G, C, A} only

Step-by-step explanation:

7 0
3 years ago
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Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth
pav-90 [236]

Answer:

\sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2). Let (x_1,y_1)\rightarrow(5,1) and (x_2,y_2)\rightarrow(3,4), thus:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}

Therefore, the distance between points P(5,1) and Q(3,4) is \sqrt{13} units.

8 0
2 years ago
Josiah traveled 79.5 miles on 3 gallons of gasoline. At this rate, how many gallons of gasoline would he need to travel 265 mile
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Josiah would need 10 gallons to travel 265 miles.

First we divide 79.5 by 3 to find out how many gallons are needed for one mile.

79.5/3=26.5

For one mile we need 26.5 gallons of gas.

Now we will divide 265 by 26.5 to find the answer to the problem.

265/26.5=10

Josiah will need 10 gallons of gas to travel 265 miles
7 0
2 years ago
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