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Gnesinka [82]
2 years ago
9

If a=(5) and b=(-3)find |a-b| (4). ( 4 )​

Mathematics
1 answer:
alexira [117]2 years ago
3 0

Answer:

8

Step-by-step explanation:

5-(-3)=8

|8|=8

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830000 in scientific notation
DedPeter [7]

Answer:

8.3 * 10 ^5

Step-by-step explanation:

830000

To change this to scientific notation, we move the decimal 5 places to the left.  The exponent will be positive 5 because we moved it to the left

8.3 * 10^ +5

8.3 * 10 ^5

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=7%20%7Bx%7D%5E%7B3%7D%20%20%2B%204x%20-%205%20%2B%208%20%7Bx%7D%5E%7B5%7D%20" id="TexFormula1"
elixir [45]

Answer:

D

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of a term within the polynomial.

Given

7x³ + 4x - 5 + 8x^{5}

The term with the largest exponent is 8x^{5} with exponent 5

Thus the polynomial is of degree 5 → D

3 0
3 years ago
Factor completely and explain 4xy-14x+16y-56​
gulaghasi [49]

Answer:

2(2y−7)(x+4)

Step-by-step explanation:

Factor 4xy−14x+16y−56

4xy−14x+16y−56

=2(2y−7)(x+4)

5 0
3 years ago
Write a compound inequality to represent all of the numbers between -4 and 6.
Oksana_A [137]
-4<n<6
...........

.........///
6 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
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